Bow damage formula?

[DeathsSilkyMist]

Originally Posted by bcbrown [You must be logged in to view images. Log in or Register.]

Thanks! Looks like the BFG uses the 2H bonus table, not the 1H values. With 1dmg arrows and unrooted the modal value is 78. When rooted with 1dmg arrows the modal value is 56. That works out to 22 + 34 = 56 and 2*22 + 34 = 78. That's the 50-delay 2H bonus at level 57. What a weird weapon. You can dual wield with it but it uses the 2h damage table.

And that means the base damage that gets doubled is (dmg + arrow dmg + 1). That's still a little strange. But I guess the standard melee damage before damage bonus is (2xdmg + 1), so if I squint I can see how it all works out. I'm close to 58 which means an increase in the damage bonus so I'll be able to do more parses in a week or so.

For melee weapons the most common damage value is generally weapon damage * 2 + damage bonus for higher level characters. You can see this in P99 parses. This is because there is a percent chance for your max damage on any swing to be capped at weapon damage * 2 + damage bonus.

I don't think BFG is using the 2h table. The math would be 21 * 2 + 34 = 76 for non-stationary and 21 * 4 + 34 = 118 for double damage. That doesn't match your numbers.

21 * 2 = 42 * 2 (double damage) = 84 * 0.783 = 65.7 + 10 = 76 rounded up is close to the 78 number you are getting for the double damage. Your previous data set was mostly using double damage attacks, so that is the better comparison value.