Bow damage formula?

[bcbrown]

The problem's all solved. We already know that melee weapons have a modal value equal to 2*dmg + bonus. I've already parsed the modal values for BFG with 1 and 3dmg arrows. They fit a pattern of damage + arrow damage + 1 + 2h damage bonus, with double damage not including the damage bonus. The modal value when unrooted with Tolan's arrows is 82. SBOZ is (2*11+10)/18 = 1.77, and 82/50 is 1.64 for BFG. Against Bloodmaw a while back I got:

bloodmaw_bfg_no_disc   0:08:49    529    72.36    89.74%    
bloodmaw_zek           0:07:22    442    74.49    93.70%

So the modal values for SBOZ and BFG pretty well predict performance against Bloodmaw, as expected. And obviously if you care about damage against a specific mob you'll want to run parses against that mob.

My ranger's out adventuring in Stonebrunt right now and I don't have fletching high enough to craft +8s yet so it'll be a while before I can run those parses, but I'm pretty confident when I run do they'll be 63 and 92.

Oh, and one more thing:

Originally Posted by DeathsSilkyMist [You must be logged in to view images. Log in or Register.]

23 * 2 + 34 = 80 damage for the non-double damage values. But he was getting mostly 82's. His double damages should be 23 * 4 + 34 = 126, but he doesn't have that many 126 damage hits.

82 is the value for the doubled hits. 58 is the value for the non-doubled hits. You're multiplying by 2 one too many times, and there's a weird +1 in the calculation.