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  #31  
Old 05-16-2013, 10:41 AM
GODPARTICLE GODPARTICLE is offline
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I liked Bardalicious before I ate his corpse, when I only slept next to it
  #32  
Old 05-16-2013, 10:43 AM
GODPARTICLE GODPARTICLE is offline
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Quote:
Originally Posted by Lubian [You must be logged in to view images. Log in or Register.]
Considering you were too retarded to even adjust the parentheses correctly, I doubt you'd understand that infinite sums are generally not associative.
Mispelled 1 sign that did not even change the outcome of the series. Also, I proved the series is convergent, so it is associative.
  #33  
Old 05-16-2013, 11:42 AM
Lazortag Lazortag is offline
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Quote:
Originally Posted by GODPARTICLE [You must be logged in to view images. Log in or Register.]
Mispelled 1 sign that did not even change the outcome of the series. Also, I proved the series is convergent, so it is associative.
You didn't prove that it was convergent. And even if you did, convergence doesn't imply associativity; for example, conditionally convergent series don't satisfy associativity.
PS: hi naez
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  #34  
Old 05-16-2013, 01:55 PM
GODPARTICLE GODPARTICLE is offline
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Well I didn't mean all sums were associative if convergent. I was referring to alternating series as we see here.

Here is the proof of convergence:

http://www.wolframalpha.com/input/?i...n-%3Einfinity+
  #35  
Old 05-16-2013, 01:56 PM
Hitchens Hitchens is offline
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You shouldn't let yourself be baited into debates with an alcoholic schizophrenic.
  #36  
Old 05-16-2013, 01:58 PM
GODPARTICLE GODPARTICLE is offline
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Further proof

http://www.wolframalpha.com/input/?i...+0+to+infinity
  #37  
Old 05-16-2013, 02:02 PM
GODPARTICLE GODPARTICLE is offline
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err should be

http://www.wolframalpha.com/input/?i...+0+to+infinity
  #38  
Old 05-16-2013, 03:45 PM
Lazortag Lazortag is offline
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Quote:
Originally Posted by GODPARTICLE [You must be logged in to view images. Log in or Register.]
Well I didn't mean all sums were associative if convergent. I was referring to alternating series as we see here.

Here is the proof of convergence:

http://www.wolframalpha.com/input/?i...n-%3Einfinity+
That's not a series, that's a sequence. Also, you put absolute value bars over it so that every term would be equal to 1. This is the correct way to input it into Wolfram: http://www.wolframalpha.com/input/?i=sum+of+%28-1%29^n

PS: I 100% fully realize that this is a troll (probably naez, maybe japan or ironlion).
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  #39  
Old 05-16-2013, 05:05 PM
GODPARTICLE GODPARTICLE is offline
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Quote:
Originally Posted by Lazortag [You must be logged in to view images. Log in or Register.]
That's not a series, that's a sequence. Also, you put absolute value bars over it so that every term would be equal to 1. This is the correct way to input it into Wolfram: http://www.wolframalpha.com/input/?i=sum+of+%28-1%29^n

PS: I 100% fully realize that this is a troll (probably naez, maybe japan or ironlion).
Yes I know it was a sequence I didn't know how to do summation on WolframAlpha. The correct summation would be:

sum of (-1+1)^n

Which does diverge via geometrical multiplicity but not arithmetically. Since we are not talking about a coordinate vector or plane of any sort, the proof stands.
  #40  
Old 05-16-2013, 05:06 PM
GODPARTICLE GODPARTICLE is offline
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Also absolute value signs are part of the calculus test for divergence.
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